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I History: 桥史
Historically, Roux (pronounced: roo; IPA: /ru/) was originally created by Gilles Roux, who has achieved a 13.03 average of 5 in competition. After the creation of the method, Austin Moore, Thom Barlow, and Jules Manalang helped to further develop the method. Alexander Lau started using Roux in 2011 and is the fastest user with the method, with a 7.00 average of 100.
桥式（Roux读/ru/）是由Gilles Roux原创的一种还原方法。他当年就有13.03的官方平均。该法问世后，Austin Moore, Thom Barlow, and Jules Manalang 几位魔友又对其进行了改进。 桥神Alexander Lau 11年转的桥党，现堪称“桥式第一人”，百次平均可达7秒的傲人成绩。
Historically, Roux (pronounced: roo; IPA: /ru/) was originally created by Gilles Roux, who has achieved a 13.03 average of 5 in competition. After the creation of the method, Austin Moore, Thom Barlow, and Jules Manalang helped to further develop the method. Alexander Lau started using Roux in 2011 and is the fastest user with the method, with a 7.00 average of 100.
桥式（Roux读/ru/）是由Gilles Roux原创的一种还原方法。他当年就有13.03的官方平均。该法问世后，Austin Moore, Thom Barlow, and Jules Manalang 几位魔友又对其进行了改进。 桥神Alexander Lau 11年转的桥党，现堪称“桥式第一人”，百次平均可达7秒的傲人成绩。
III. Advantages and Disadvantages: 优缺点
Advantages:优点 - Very move efficient废步少 - Few Algorithms公式量小 - No rotations转体少 - Very intuitive好观察 Disadvantages:缺点 - Not as algorithmic, so good lookahead is required to be fast.不那么的公式化，所以预判很重要。 - Requires lots of thinking when first starting because blockbuilding is involved 为搭桥需要，开始前前要思考很多东西。
You should use Roux if:这样子你就可以转桥党： -You are not good at learning algorithms不擅长学公式。 -You want to solve the cube with a mostly intuitive method想边看边凭感觉将魔方还原回去。 -You want to finish your solve with some sexy M slice
Advantages:优点 - Very move efficient废步少 - Few Algorithms公式量小 - No rotations转体少 - Very intuitive好观察 Disadvantages:缺点 - Not as algorithmic, so good lookahead is required to be fast.不那么的公式化，所以预判很重要。 - Requires lots of thinking when first starting because blockbuilding is involved 为搭桥需要，开始前前要思考很多东西。
You should use Roux if:这样子你就可以转桥党： -You are not good at learning algorithms不擅长学公式。 -You want to solve the cube with a mostly intuitive method想边看边凭感觉将魔方还原回去。 -You want to finish your solve with some sexy M slice
V. Color Neutrality in Roux:桥式六色底
Very few people are fully Color Neutral with roux due to the difficulty during the blockbuilding step. There are two common forms of partial color neutrality in Roux. The first is <x2, y, z2> neutrality, which is similar to opposite neutrality in CFOP - the solver uses only opposite colors for the U and D faces (e.g., using white/yellow for U/D). The other form of partial color neutrality is, or using only opposite colors for L and R faces. Though each form gives a mathematically equal number of different options for the blocks, it is generally agreed that <x, y2, z2> gives more options for the blocks, though makes CMLL recognition more challenging.
由于搭桥一步，桥式纯六色底的少得可怜，但还是有两种形式的部分六色底。第一种是做<x, y2, z2>转体类，其效果类似于FOP中的双色底----顶底双色。另一种是做<x, y2, z2>转体类，或者只将左右两桥的颜色对换过来。虽然二者在搭桥选择上旗鼓相当，但是通常来说，<x, y2, z2>转体类更好搭桥些----但是也使得CMLL识别更难。
Very few people are fully Color Neutral with roux due to the difficulty during the blockbuilding step. There are two common forms of partial color neutrality in Roux. The first is <x2, y, z2> neutrality, which is similar to opposite neutrality in CFOP - the solver uses only opposite colors for the U and D faces (e.g., using white/yellow for U/D). The other form of partial color neutrality is, or using only opposite colors for L and R faces. Though each form gives a mathematically equal number of different options for the blocks, it is generally agreed that <x, y2, z2> gives more options for the blocks, though makes CMLL recognition more challenging.
由于搭桥一步，桥式纯六色底的少得可怜，但还是有两种形式的部分六色底。第一种是做<x, y2, z2>转体类，其效果类似于FOP中的双色底----顶底双色。另一种是做<x, y2, z2>转体类，或者只将左右两桥的颜色对换过来。虽然二者在搭桥选择上旗鼓相当，但是通常来说，<x, y2, z2>转体类更好搭桥些----但是也使得CMLL识别更难。
VI. Roux Variants: 桥式变体
-CMLL+EO is an extension on CMLL that orients the edges during CMLL so that step can be skipped during LSE. However, the large number of algorithms required for each CMLL case cause few people to decide to learn this. It is comparable to learning ZB or OLLCP in the CFOP method. http://www.speedsolving.com/forum/sh...php?21210-KCLL
CMLL+EO是CMLL对的延伸版，在做CMLL时就将棱给调好，相当于跳了一步直接做LSE.但是不同情况所带来的巨大公式量往往让人望而却步。这种变体类似于在CFOP中用ZB或者OLLCP一样
-Non-matching Blocks is a self-explanatory name. The second block does not need to match the first block, giving 4 options for the second block, instead of just 1. This allows the second block to be much faster, but makes CMLL, LSE and EO much more difficult. Here is a page about non-matching CMLL that will occur when using non-matching blocks:
Non-matching Blocks（不等桥）这个名字的含义不言而喻，就是说第二桥不需要和第一个桥是相对应的。这样一来第二桥就有四种搭法，而不是一种。这意味着搭第二桥的速度会快很多。但是这么一来，CMLL,LSE,和 EO的难度扶摇直上。下面这个
页面里介绍了与不等桥相关的内容。
http://www.speedsolving.com/wiki/index.php/NMCLL
-CMLL+EO is an extension on CMLL that orients the edges during CMLL so that step can be skipped during LSE. However, the large number of algorithms required for each CMLL case cause few people to decide to learn this. It is comparable to learning ZB or OLLCP in the CFOP method. http://www.speedsolving.com/forum/sh...php?21210-KCLL
CMLL+EO是CMLL对的延伸版，在做CMLL时就将棱给调好，相当于跳了一步直接做LSE.但是不同情况所带来的巨大公式量往往让人望而却步。这种变体类似于在CFOP中用ZB或者OLLCP一样
-Non-matching Blocks is a self-explanatory name. The second block does not need to match the first block, giving 4 options for the second block, instead of just 1. This allows the second block to be much faster, but makes CMLL, LSE and EO much more difficult. Here is a page about non-matching CMLL that will occur when using non-matching blocks:
Non-matching Blocks（不等桥）这个名字的含义不言而喻，就是说第二桥不需要和第一个桥是相对应的。这样一来第二桥就有四种搭法，而不是一种。这意味着搭第二桥的速度会快很多。但是这么一来，CMLL,LSE,和 EO的难度扶摇直上。下面这个
页面里介绍了与不等桥相关的内容。
http://www.speedsolving.com/wiki/index.php/NMCLL
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